Half Life Rate Law at Life

Half Life Rate Law. K = 2.0 × 10 −2 mol/l/h (about 0.9 g/l/h for the average male); If we replace this idea on the integrated rate law we get:

Find order and rate of rxn find order hci (fix conc ester) rate = k[hci]1[ester]1 1st order respect to hci using initial rate and half life for order expt 1 expt 2 time/m [ester]/m in [hci] = 0.1 [ester]/m in [hci] = 0.2 0 0.200 0.200 25 0.152 0.115 50 0.115 0.067 75 0.088 0.038 100 0.067 0.022 120 0.051 0.013 time conc ester gradient, rate = 1. If the plot is a straight line, then the integrated rate law equation can be used to find the rate constant, k, or the slope of the line can be calculated for the rate constant. T ½ = [a o] / 2k for a first order reaction a products , rate = k[a]:

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The reaction is zero order. Kt ½ = 0.693 t½ = 2.3 ×102 s = 3.9 min dr. [a] 0 is the initial concentration. (a) the process reduces the rate by a factor of 4.